Base | Representation |
---|---|
bin | 11101100100111101111101… |
… | …001110111100101000000010 |
3 | 122001120212221222111220022020 |
4 | 131210331331032330220002 |
5 | 114022243033021024130 |
6 | 1140355354515022310 |
7 | 36254146140230232 |
oct | 3544757516745002 |
9 | 561525858456266 |
10 | 130083775564290 |
11 | 384a3246035679 |
12 | 1270b13529a996 |
13 | 5777b02979cc2 |
14 | 241a134547cc2 |
15 | 1008b9e257e10 |
hex | 764f7d3bca02 |
130083775564290 has 64 divisors (see below), whose sum is σ = 317357028743040. Its totient is φ = 34116257456640.
The previous prime is 130083775564271. The next prime is 130083775564319. The reversal of 130083775564290 is 92465577380031.
It is a happy number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 11087101 + ... + 19572719.
It is an arithmetic number, because the mean of its divisors is an integer number (4958703574110).
It is a 1-persistent number, because it is pandigital, but 2⋅130083775564290 = 260167551128580 is not.
Almost surely, 2130083775564290 is an apocalyptic number.
130083775564290 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
130083775564290 is an abundant number, since it is smaller than the sum of its proper divisors (187273253178750).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130083775564290 is a wasteful number, since it uses less digits than its factorization.
130083775564290 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8494067.
The product of its (nonzero) digits is 38102400, while the sum is 60.
The spelling of 130083775564290 in words is "one hundred thirty trillion, eighty-three billion, seven hundred seventy-five million, five hundred sixty-four thousand, two hundred ninety".
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