Base | Representation |
---|---|
bin | 11101100101001101010110… |
… | …110101011001110010111000 |
3 | 122001122110122101020101021120 |
4 | 131211031112311121302320 |
5 | 114023030414131444000 |
6 | 1140411131411105240 |
7 | 36255302664646365 |
oct | 3545152665316270 |
9 | 561573571211246 |
10 | 130100311203000 |
11 | 384aa260a69796 |
12 | 1271238aba2220 |
13 | 57795396b59c8 |
14 | 241ac626ab46c |
15 | 100931aca66a0 |
hex | 765356d59cb8 |
130100311203000 has 64 divisors (see below), whose sum is σ = 405912970962720. Its totient is φ = 34693416320000.
The previous prime is 130100311202941. The next prime is 130100311203001. The reversal of 130100311203000 is 302113001031.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130100311203001) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 21683382201 + ... + 21683388200.
Almost surely, 2130100311203000 is an apocalyptic number.
130100311203000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
130100311203000 is an abundant number, since it is smaller than the sum of its proper divisors (275812659759720).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130100311203000 is a wasteful number, since it uses less digits than its factorization.
130100311203000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 43366770425 (or 43366770411 counting only the distinct ones).
The product of its (nonzero) digits is 54, while the sum is 15.
Adding to 130100311203000 its reverse (302113001031), we get a palindrome (130402424204031).
The spelling of 130100311203000 in words is "one hundred thirty trillion, one hundred billion, three hundred eleven million, two hundred three thousand".
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