Base | Representation |
---|---|
bin | 1011110101010110100010… |
… | …0111111010100000010100 |
3 | 1201001212012200102012010110 |
4 | 2331111220213322200110 |
5 | 3201133430033431200 |
6 | 43401133512123020 |
7 | 2512012641455640 |
oct | 275255047724024 |
9 | 51055180365113 |
10 | 13011211233300 |
11 | 41670295a3265 |
12 | 15617b0396470 |
13 | 734c4b5a1087 |
14 | 32da62d9dc20 |
15 | 1786b8a4db50 |
hex | bd5689fa814 |
13011211233300 has 144 divisors (see below), whose sum is σ = 43297776126080. Its totient is φ = 2955048445440.
The previous prime is 13011211233299. The next prime is 13011211233311. The reversal of 13011211233300 is 333211211031.
It is a happy number.
13011211233300 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a Harshad number since it is a multiple of its sum of digits (21).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 19402195 + ... + 20061594.
Almost surely, 213011211233300 is an apocalyptic number.
13011211233300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13011211233300 is an abundant number, since it is smaller than the sum of its proper divisors (30286564892780).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13011211233300 is a wasteful number, since it uses less digits than its factorization.
13011211233300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 39463970 (or 39463963 counting only the distinct ones).
The product of its (nonzero) digits is 324, while the sum is 21.
Adding to 13011211233300 its reverse (333211211031), we get a palindrome (13344422444331).
The spelling of 13011211233300 in words is "thirteen trillion, eleven billion, two hundred eleven million, two hundred thirty-three thousand, three hundred".
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