1301121212100 has 144 divisors (see below), whose sum is σ = 3829901745600. Its totient is φ = 340949649920.

The previous prime is 1301121212057. The next prime is 1301121212107. The reversal of 1301121212100 is 12121211031.

It is a super-3 number, since 3×1301121212100³ (a number of 37 digits) contains 333 as substring.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a self number, because there is not a number n which added to its sum of digits gives 1301121212100.

It is not an unprimeable number, because it can be changed into a prime (1301121212107) by changing a digit.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 49352122 + ... + 49378478.

It is an arithmetic number, because the mean of its divisors is an integer number (26596539900).

Almost surely, 2^{1301121212100} is an apocalyptic number.

1301121212100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1301121212100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1914950872800).

1301121212100 is an abundant number, since it is smaller than the sum of its proper divisors (2528780533500).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1301121212100 is a wasteful number, since it uses less digits than its factorization.

1301121212100 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 29222 (or 29215 counting only the distinct ones).

The product of its (nonzero) digits is 24, while the sum is 15.

Adding to 1301121212100 its reverse (12121211031), we get a palindrome (1313242423131).

The spelling of 1301121212100 in words is "one trillion, three hundred one billion, one hundred twenty-one million, two hundred twelve thousand, one hundred".