Base | Representation |
---|---|
bin | 10010111101101001001… |
… | …110000111101110000000 |
3 | 11121120122002120022011021 |
4 | 102331221032013232000 |
5 | 132322312420300000 |
6 | 2434353205155224 |
7 | 163102014431455 |
oct | 22755116075600 |
9 | 4546562508137 |
10 | 1303140400000 |
11 | 46272786819a |
12 | 1906830bbb14 |
13 | 95b688c90aa |
14 | 4710269b82c |
15 | 23d6e99e11a |
hex | 12f69387b80 |
1303140400000 has 96 divisors (see below), whose sum is σ = 3244918327560. Its totient is φ = 521256000000.
The previous prime is 1303140399989. The next prime is 1303140400073. The reversal of 1303140400000 is 40413031.
It is a super-2 number, since 2×13031404000002 (a number of 25 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (16).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1228926 + ... + 2028925.
Almost surely, 21303140400000 is an apocalyptic number.
1303140400000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1303140400000 is an abundant number, since it is smaller than the sum of its proper divisors (1941777927560).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1303140400000 is an frugal number, since it uses more digits than its factorization.
1303140400000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3257890 (or 3257858 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 16.
Adding to 1303140400000 its reverse (40413031), we get a palindrome (1303180813031).
The spelling of 1303140400000 in words is "one trillion, three hundred three billion, one hundred forty million, four hundred thousand".
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