1303243034112 has 120 divisors (see below), whose sum is σ = 3761765779200. Its totient is φ = 434354503680.

The previous prime is 1303243034047. The next prime is 1303243034113. The reversal of 1303243034112 is 2114303423031.

It is a happy number.

1303243034112 is a `hidden beast` number, since 1 + 3 + 0 + 3 + 243 + 0 + 3 + 411 + 2 = 666.

It is a super-2 number, since 2×1303243034112² (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1303243034113) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 44447937 + ... + 44477247.

It is an arithmetic number, because the mean of its divisors is an integer number (31348048160).

Almost surely, 2^{1303243034112} is an apocalyptic number.

1303243034112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1303243034112, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1880882889600).

1303243034112 is an abundant number, since it is smaller than the sum of its proper divisors (2458522745088).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1303243034112 is an equidigital number, since it uses as much as digits as its factorization.

1303243034112 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 38984 (or 38965 counting only the distinct ones).

The product of its (nonzero) digits is 5184, while the sum is 27.

Adding to 1303243034112 its reverse (2114303423031), we get a palindrome (3417546457143).

The spelling of 1303243034112 in words is "one trillion, three hundred three billion, two hundred forty-three million, thirty-four thousand, one hundred twelve".