Base | Representation |
---|---|
bin | 10010111110011110010… |
… | …111110100010000111000 |
3 | 11121122221020112002111212 |
4 | 102332132113310100320 |
5 | 132331124211243300 |
6 | 2435021502142252 |
7 | 163133063152565 |
oct | 22763627642070 |
9 | 4548836462455 |
10 | 1304032134200 |
11 | 463045164304 |
12 | 190891881988 |
13 | 95c7b58a373 |
14 | 47188ca586c |
15 | 23dc2de6935 |
hex | 12f9e5f4438 |
1304032134200 has 96 divisors (see below), whose sum is σ = 3221566194960. Its totient is φ = 489194649600.
The previous prime is 1304032134131. The next prime is 1304032134211. The reversal of 1304032134200 is 24312304031.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 284570 + ... + 1639830.
Almost surely, 21304032134200 is an apocalyptic number.
1304032134200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 1304032134200, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1610783097480).
1304032134200 is an abundant number, since it is smaller than the sum of its proper divisors (1917534060760).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1304032134200 is a wasteful number, since it uses less digits than its factorization.
1304032134200 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1355577 (or 1355568 counting only the distinct ones).
The product of its (nonzero) digits is 1728, while the sum is 23.
Adding to 1304032134200 its reverse (24312304031), we get a palindrome (1328344438231).
The spelling of 1304032134200 in words is "one trillion, three hundred four billion, thirty-two million, one hundred thirty-four thousand, two hundred".
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