Base | Representation |
---|---|
bin | 1011110111011000101000… |
… | …0110111001111101101000 |
3 | 1201012012100102101202001010 |
4 | 2331312022012321331220 |
5 | 3202221434440302130 |
6 | 43425151033223520 |
7 | 2514360221430414 |
oct | 275661206717550 |
9 | 51165312352033 |
10 | 13046132744040 |
11 | 417a919905140 |
12 | 1568517561ba0 |
13 | 7383254731b6 |
14 | 331616cb7d44 |
15 | 17955e7780b0 |
hex | bdd8a1b9f68 |
13046132744040 has 64 divisors (see below), whose sum is σ = 42696434439360. Its totient is φ = 3162698846720.
The previous prime is 13046132743901. The next prime is 13046132744081. The reversal of 13046132744040 is 4044723164031.
It is a super-2 number, since 2×130461327440402 (a number of 27 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 13046132744040.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4941715629 + ... + 4941718268.
It is an arithmetic number, because the mean of its divisors is an integer number (667131788115).
Almost surely, 213046132744040 is an apocalyptic number.
13046132744040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13046132744040 is an abundant number, since it is smaller than the sum of its proper divisors (29650301695320).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13046132744040 is a wasteful number, since it uses less digits than its factorization.
13046132744040 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9883433922 (or 9883433918 counting only the distinct ones).
The product of its (nonzero) digits is 193536, while the sum is 39.
The spelling of 13046132744040 in words is "thirteen trillion, forty-six billion, one hundred thirty-two million, seven hundred forty-four thousand, forty".
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