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130503011312000 = 27538156438207
BaseRepresentation
bin11101101011000100011001…
…101000011010000110000000
3122010001222002020112111111102
4131223010121220122012000
5114101130131343441000
61141320131124033532
736326350164256325
oct3553043150320600
9563058066474442
10130503011312000
113864501a751a28
12127784365328a8
1357a84c5548282
1424325452d0b4c
151014a397573d5
hex76b119a1a180

130503011312000 has 64 divisors (see below), whose sum is σ = 324463111914240. Its totient is φ = 52201204518400.

The previous prime is 130503011311903. The next prime is 130503011312021. The reversal of 130503011312000 is 213110305031.

It is a tau number, because it is divible by the number of its divisors (64).

It is a super-2 number, since 2×1305030113120002 (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4078203104 + ... + 4078235103.

It is an arithmetic number, because the mean of its divisors is an integer number (5069736123660).

Almost surely, 2130503011312000 is an apocalyptic number.

130503011312000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

130503011312000 is an abundant number, since it is smaller than the sum of its proper divisors (193960100602240).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130503011312000 is an frugal number, since it uses more digits than its factorization.

130503011312000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8156438236 (or 8156438214 counting only the distinct ones).

The product of its (nonzero) digits is 270, while the sum is 20.

Adding to 130503011312000 its reverse (213110305031), we get a palindrome (130716121617031).

The spelling of 130503011312000 in words is "one hundred thirty trillion, five hundred three billion, eleven million, three hundred twelve thousand".

Divisors: 1 2 4 5 8 10 16 20 25 32 40 50 64 80 100 125 128 160 200 250 320 400 500 640 800 1000 1600 2000 3200 4000 8000 16000 8156438207 16312876414 32625752828 40782191035 65251505656 81564382070 130503011312 163128764140 203910955175 261006022624 326257528280 407821910350 522012045248 652515056560 815643820700 1019554775875 1044024090496 1305030113120 1631287641400 2039109551750 2610060226240 3262575282800 4078219103500 5220120452480 6525150565600 8156438207000 13050301131200 16312876414000 26100602262400 32625752828000 65251505656000 130503011312000