13100113200 has 60 divisors (see below), whose sum is σ = 41964033128. Its totient is φ = 3493363200.

The previous prime is 13100113193. The next prime is 13100113277. The reversal of 13100113200 is 231100131.

13100113200 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a tau number, because it is divible by the number of its divisors (60).

It is a super-2 number, since 2×13100113200² (a number of 21 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (12).

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 5457181 + ... + 5459580.

Almost surely, 2^13100113200 is an apocalyptic number.

13100113200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13100113200 is an abundant number, since it is smaller than the sum of its proper divisors (28863919928).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13100113200 is a wasteful number, since it uses less digits than its factorization.

13100113200 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10916782 (or 10916771 counting only the distinct ones).

The product of its (nonzero) digits is 18, while the sum is 12.

Adding to 13100113200 its reverse (231100131), we get a palindrome (13331213331).

The spelling of 13100113200 in words is "thirteen billion, one hundred million, one hundred thirteen thousand, two hundred".