13102103320 has 64 divisors (see below), whose sum is σ = 31302832320. Its totient is φ = 4918493184.

The previous prime is 13102103297. The next prime is 13102103351. The reversal of 13102103320 is 2330120131.

It is a super-2 number, since 2×13102103320² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13102103294 and 13102103303.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 212749 + ... + 267331.

It is an arithmetic number, because the mean of its divisors is an integer number (489106755).

Almost surely, 2^13102103320 is an apocalyptic number.

13102103320 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13102103320, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (15651416160).

13102103320 is an abundant number, since it is smaller than the sum of its proper divisors (18200729000).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13102103320 is a wasteful number, since it uses less digits than its factorization.

13102103320 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 54964 (or 54960 counting only the distinct ones).

The product of its (nonzero) digits is 108, while the sum is 16.

Adding to 13102103320 its reverse (2330120131), we get a palindrome (15432223451).

The spelling of 13102103320 in words is "thirteen billion, one hundred two million, one hundred three thousand, three hundred twenty".