131023113000 has 128 divisors (see below), whose sum is σ = 440237790720. Its totient is φ = 32251833600.

The previous prime is 131023112993. The next prime is 131023113019. The reversal of 131023113000 is 311320131.

It is a super-4 number, since 4×131023113000⁴ (a number of 46 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1640784 + ... + 1718783.

It is an arithmetic number, because the mean of its divisors is an integer number (3439357740).

Almost surely, 2^131023113000 is an apocalyptic number.

131023113000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

131023113000 is an abundant number, since it is smaller than the sum of its proper divisors (309214677720).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131023113000 is a wasteful number, since it uses less digits than its factorization.

131023113000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3359604 (or 3359590 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 131023113000 its reverse (311320131), we get a palindrome (131334433131).

It can be divided in two parts, 1310231 and 13000, that added together give a palindrome (1323231).

The spelling of 131023113000 in words is "one hundred thirty-one billion, twenty-three million, one hundred thirteen thousand".