13104421114240 has 32 divisors (see below), whose sum is σ = 31327756727760. Its totient is φ = 5241768445440.

The previous prime is 13104421114237. The next prime is 13104421114241. The reversal of 13104421114240 is 4241112440131.

It is a happy number.

It is a tau number, because it is divible by the number of its divisors (32).

It is a junction number, because it is equal to n+sod(n) for n = 13104421114199 and 13104421114208.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13104421114241) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10237828356 + ... + 10237829635.

Almost surely, 2^{13104421114240} is an apocalyptic number.

13104421114240 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13104421114240 is an abundant number, since it is smaller than the sum of its proper divisors (18223335613520).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13104421114240 is an equidigital number, since it uses as much as digits as its factorization.

13104421114240 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 20475658010 (or 20475657998 counting only the distinct ones).

The product of its (nonzero) digits is 3072, while the sum is 28.

Adding to 13104421114240 its reverse (4241112440131), we get a palindrome (17345533554371).

The spelling of 13104421114240 in words is "thirteen trillion, one hundred four billion, four hundred twenty-one million, one hundred fourteen thousand, two hundred forty".