Base | Representation |
---|---|
bin | 1011111010110101011011… |
… | …1010001011010101010000 |
3 | 1201101212100002102112101010 |
4 | 2332231112322023111100 |
5 | 3204204331221431230 |
6 | 43512312243210520 |
7 | 2521556053100436 |
oct | 276552672132520 |
9 | 51355302375333 |
10 | 13105403311440 |
11 | 41a2a7456a740 |
12 | 1577ab9076a40 |
13 | 740aaca5735b |
14 | 33443a930d56 |
15 | 17ad7ce429b0 |
hex | beb56e8b550 |
13105403311440 has 160 divisors (see below), whose sum is σ = 44422925893632. Its totient is φ = 3169695808000.
The previous prime is 13105403311439. The next prime is 13105403311453. The reversal of 13105403311440 is 4411330450131.
It is a Harshad number since it is a multiple of its sum of digits (30).
It is a junction number, because it is equal to n+sod(n) for n = 13105403311398 and 13105403311407.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 4621056 + ... + 6896735.
Almost surely, 213105403311440 is an apocalyptic number.
13105403311440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13105403311440 is an abundant number, since it is smaller than the sum of its proper divisors (31317522582192).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13105403311440 is a wasteful number, since it uses less digits than its factorization.
13105403311440 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11518249 (or 11518243 counting only the distinct ones).
The product of its (nonzero) digits is 8640, while the sum is 30.
Adding to 13105403311440 its reverse (4411330450131), we get a palindrome (17516733761571).
The spelling of 13105403311440 in words is "thirteen trillion, one hundred five billion, four hundred three million, three hundred eleven thousand, four hundred forty".
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