Base | Representation |
---|---|
bin | 1011111011001010011010… |
… | …0011001111000100010000 |
3 | 1201102101212112101121022020 |
4 | 2332302212203033010100 |
5 | 3204302344304121000 |
6 | 43515043122011440 |
7 | 2522145440651625 |
oct | 276624643170420 |
9 | 51371775347266 |
10 | 13111034442000 |
11 | 41a53a4158450 |
12 | 157900aaa6b80 |
13 | 741499591281 |
14 | 33481276034c |
15 | 17b0ac4b5ba0 |
hex | beca68cf110 |
13111034442000 has 160 divisors (see below), whose sum is σ = 46112700276864. Its totient is φ = 3178432576000.
The previous prime is 13111034441977. The next prime is 13111034442001. The reversal of 13111034442000 is 24443011131.
It is a Harshad number since it is a multiple of its sum of digits (24).
It is not an unprimeable number, because it can be changed into a prime (13111034442001) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 99260019 + ... + 99392018.
Almost surely, 213111034442000 is an apocalyptic number.
13111034442000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13111034442000 is an abundant number, since it is smaller than the sum of its proper divisors (33001665834864).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13111034442000 is a wasteful number, since it uses less digits than its factorization.
13111034442000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 198652074 (or 198652058 counting only the distinct ones).
The product of its (nonzero) digits is 1152, while the sum is 24.
Adding to 13111034442000 its reverse (24443011131), we get a palindrome (13135477453131).
The spelling of 13111034442000 in words is "thirteen trillion, one hundred eleven billion, thirty-four million, four hundred forty-two thousand".
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