13111433120 has 96 divisors (see below), whose sum is σ = 31697749440. Its totient is φ = 5123450880.

The previous prime is 13111433119. The next prime is 13111433171. The reversal of 13111433120 is 2133411131.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is a junction number, because it is equal to n+sod(n) for n = 13111433092 and 13111433101.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1534460 + ... + 1542980.

It is an arithmetic number, because the mean of its divisors is an integer number (330184890).

Almost surely, 2^13111433120 is an apocalyptic number.

13111433120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13111433120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (15848874720).

13111433120 is an abundant number, since it is smaller than the sum of its proper divisors (18586316320).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13111433120 is a wasteful number, since it uses less digits than its factorization.

13111433120 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8758 (or 8750 counting only the distinct ones).

The product of its (nonzero) digits is 216, while the sum is 20.

Adding to 13111433120 its reverse (2133411131), we get a palindrome (15244844251).

The spelling of 13111433120 in words is "thirteen billion, one hundred eleven million, four hundred thirty-three thousand, one hundred twenty".