13113102022400 has 108 divisors (see below), whose sum is σ = 32506089753144. Its totient is φ = 5237303808000.

The previous prime is 13113102022399. The next prime is 13113102022421. The reversal of 13113102022400 is 422020131131.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 2680535 + ... + 5780265.

Almost surely, 2^{13113102022400} is an apocalyptic number.

13113102022400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13113102022400, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (16253044876572).

13113102022400 is an abundant number, since it is smaller than the sum of its proper divisors (19392987730744).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13113102022400 is an equidigital number, since it uses as much as digits as its factorization.

13113102022400 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3100418 (or 3100399 counting only the distinct ones).

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 13113102022400 its reverse (422020131131), we get a palindrome (13535122153531).

The spelling of 13113102022400 in words is "thirteen trillion, one hundred thirteen billion, one hundred two million, twenty-two thousand, four hundred".