Base | Representation |
---|---|
bin | 10011000101010000011… |
… | …001111110000101000000 |
3 | 11122100201201122201210120 |
4 | 103011100121332011000 |
5 | 132441032341313212 |
6 | 2442224230100240 |
7 | 163511404115466 |
oct | 23052031760500 |
9 | 4570651581716 |
10 | 1311314010432 |
11 | 466141633738 |
12 | 1921844aa680 |
13 | 9686c0b697a |
14 | 4767a038836 |
15 | 2419c33e88c |
hex | 1315067e140 |
1311314010432 has 28 divisors (see below), whose sum is σ = 3469518319776. Its totient is φ = 437104670080.
The previous prime is 1311314010431. The next prime is 1311314010527. The reversal of 1311314010432 is 2340104131131.
It is a happy number.
It is a Harshad number since it is a multiple of its sum of digits (24).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1311314010431) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3414880044 + ... + 3414880427.
Almost surely, 21311314010432 is an apocalyptic number.
1311314010432 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
1311314010432 is an abundant number, since it is smaller than the sum of its proper divisors (2158204309344).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1311314010432 is an equidigital number, since it uses as much as digits as its factorization.
1311314010432 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6829760486 (or 6829760476 counting only the distinct ones).
The product of its (nonzero) digits is 864, while the sum is 24.
Adding to 1311314010432 its reverse (2340104131131), we get a palindrome (3651418141563).
The spelling of 1311314010432 in words is "one trillion, three hundred eleven billion, three hundred fourteen million, ten thousand, four hundred thirty-two".
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