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131142400130000 = 245471873462859
BaseRepresentation
bin11101110100010111111000…
…001011001011101111010000
3122012100002110100101211101202
4131310113320023023233100
5114142114113413130000
61142525553101250332
736423503633454410
oct3564277013135720
9565302410354352
10131142400130000
11388711a7aa8476
12128603385639a8
1358238a174587c
14245547c8c8640
1510264ac5d0dd5
hex7745f82cbbd0

131142400130000 has 100 divisors (see below), whose sum is σ = 362867274427680. Its totient is φ = 44963108592000.

The previous prime is 131142400129997. The next prime is 131142400130003. The reversal of 131142400130000 is 31004241131.

It is an interprime number because it is at equal distance from previous prime (131142400129997) and next prime (131142400130003).

It is a tau number, because it is divible by the number of its divisors (100).

It is a super-5 number, since 5×1311424001300005 (a number of 72 digits) contains 55555 as substring. Note that it is a super-d number also for d = 2.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131142400130003) by changing a digit.

It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 936661430 + ... + 936801429.

Almost surely, 2131142400130000 is an apocalyptic number.

131142400130000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

131142400130000 is an abundant number, since it is smaller than the sum of its proper divisors (231724874297680).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131142400130000 is an equidigital number, since it uses as much as digits as its factorization.

131142400130000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1873462894 (or 1873462873 counting only the distinct ones).

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 131142400130000 its reverse (31004241131), we get a palindrome (131173404371131).

The spelling of 131142400130000 in words is "one hundred thirty-one trillion, one hundred forty-two billion, four hundred million, one hundred thirty thousand".

Divisors: 1 2 4 5 7 8 10 14 16 20 25 28 35 40 50 56 70 80 100 112 125 140 175 200 250 280 350 400 500 560 625 700 875 1000 1250 1400 1750 2000 2500 2800 3500 4375 5000 7000 8750 10000 14000 17500 35000 70000 1873462859 3746925718 7493851436 9367314295 13114240013 14987702872 18734628590 26228480026 29975405744 37469257180 46836571475 52456960052 65571200065 74938514360 93673142950 104913920104 131142400130 149877028720 187346285900 209827840208 234182857375 262284800260 327856000325 374692571800 468365714750 524569600520 655712000650 749385143600 936731429500 1049139201040 1170914286875 1311424001300 1639280001625 1873462859000 2341828573750 2622848002600 3278560003250 3746925718000 4683657147500 5245696005200 6557120006500 8196400008125 9367314295000 13114240013000 16392800016250 18734628590000 26228480026000 32785600032500 65571200065000 131142400130000