Base | Representation |
---|---|
bin | 11000011011011101… |
… | …00110111111000000 |
3 | 1020212000121102002001 |
4 | 30031232212333000 |
5 | 203324444132000 |
6 | 10005224433344 |
7 | 643002364444 |
oct | 141556467700 |
9 | 36760542061 |
10 | 13115224000 |
11 | 56202249aa |
12 | 2660318854 |
13 | 1310215a98 |
14 | 8c5ba0824 |
15 | 51b61246a |
hex | 30dba6fc0 |
13115224000 has 112 divisors (see below), whose sum is σ = 32611344480. Its totient is φ = 5224857600.
The previous prime is 13115223991. The next prime is 13115224007. The reversal of 13115224000 is 42251131.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13115224007) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2052811 + ... + 2059189.
Almost surely, 213115224000 is an apocalyptic number.
13115224000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 13115224000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (16305672240).
13115224000 is an abundant number, since it is smaller than the sum of its proper divisors (19496120480).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13115224000 is an equidigital number, since it uses as much as digits as its factorization.
13115224000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6663 (or 6643 counting only the distinct ones).
The product of its (nonzero) digits is 240, while the sum is 19.
Adding to 13115224000 its reverse (42251131), we get a palindrome (13157475131).
The spelling of 13115224000 in words is "thirteen billion, one hundred fifteen million, two hundred twenty-four thousand".
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