Base | Representation |
---|---|
bin | 100111000101111… |
… | …0010111000011000 |
3 | 10101102020000111010 |
4 | 1032023302320120 |
5 | 10141244333330 |
6 | 334054333520 |
7 | 44335251342 |
oct | 11613627030 |
9 | 3342200433 |
10 | 1311714840 |
11 | 613479857 |
12 | 30735a2a0 |
13 | 17b9aa237 |
14 | c62d0292 |
15 | 7a2563b0 |
hex | 4e2f2e18 |
1311714840 has 128 divisors (see below), whose sum is σ = 4118169600. Its totient is φ = 333611520.
The previous prime is 1311714839. The next prime is 1311714851. The reversal of 1311714840 is 484171131.
It is a Harshad number since it is a multiple of its sum of digits (30).
It is a junction number, because it is equal to n+sod(n) for n = 1311714798 and 1311714807.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1824001 + ... + 1824719.
It is an arithmetic number, because the mean of its divisors is an integer number (32173200).
Almost surely, 21311714840 is an apocalyptic number.
1311714840 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 1311714840, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2059084800).
1311714840 is an abundant number, since it is smaller than the sum of its proper divisors (2806454760).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1311714840 is a wasteful number, since it uses less digits than its factorization.
1311714840 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1417 (or 1413 counting only the distinct ones).
The product of its (nonzero) digits is 2688, while the sum is 30.
The square root of 1311714840 is about 36217.6040068915. The cubic root of 1311714840 is about 1094.6614161366.
Adding to 1311714840 its reverse (484171131), we get a palindrome (1795885971).
The spelling of 1311714840 in words is "one billion, three hundred eleven million, seven hundred fourteen thousand, eight hundred forty".
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