Base | Representation |
---|---|
bin | 10011000101111011111… |
… | …000001100110010101110 |
3 | 11122102121120001021212211 |
4 | 103011323320030302232 |
5 | 132444031044332220 |
6 | 2442424442321034 |
7 | 163535441336422 |
oct | 23057370146256 |
9 | 4572546037784 |
10 | 1312043355310 |
11 | 4664862a62a6 |
12 | 1923487b917a |
13 | 9695722ba9c |
14 | 47708c50b82 |
15 | 241e13abb5a |
hex | 1317be0ccae |
1312043355310 has 96 divisors (see below), whose sum is σ = 2440325361600. Its totient is φ = 507877945344.
The previous prime is 1312043355307. The next prime is 1312043355319. The reversal of 1312043355310 is 135533402131.
It is a happy number.
It is a super-2 number, since 2×13120433553102 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1312043355319) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 1078095822 + ... + 1078097038.
It is an arithmetic number, because the mean of its divisors is an integer number (25420055850).
Almost surely, 21312043355310 is an apocalyptic number.
1312043355310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
1312043355310 is a deficient number, since it is larger than the sum of its proper divisors (1128282006290).
1312043355310 is a wasteful number, since it uses less digits than its factorization.
1312043355310 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1802 (or 1759 counting only the distinct ones).
The product of its (nonzero) digits is 16200, while the sum is 31.
Adding to 1312043355310 its reverse (135533402131), we get a palindrome (1447576757441).
The spelling of 1312043355310 in words is "one trillion, three hundred twelve billion, forty-three million, three hundred fifty-five thousand, three hundred ten".
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