Base | Representation |
---|---|
bin | 1011111011110000101100… |
… | …0011010010101000101100 |
3 | 1201110101101200121111202120 |
4 | 2332330023003102220230 |
5 | 3204434420442021140 |
6 | 43523502525352540 |
7 | 2522661210012552 |
oct | 276741303225054 |
9 | 51411350544676 |
10 | 13121310501420 |
11 | 41a9797784a40 |
12 | 157abb8408750 |
13 | 7424465165c4 |
14 | 335109423bd2 |
15 | 17b4ae7041d0 |
hex | bef0b0d2a2c |
13121310501420 has 96 divisors (see below), whose sum is σ = 40080681398016. Its totient is φ = 3180841056000.
The previous prime is 13121310501391. The next prime is 13121310501437. The reversal of 13121310501420 is 2410501312131.
13121310501420 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 27384142 + ... + 27859178.
It is an arithmetic number, because the mean of its divisors is an integer number (417507097896).
Almost surely, 213121310501420 is an apocalyptic number.
13121310501420 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13121310501420 is an abundant number, since it is smaller than the sum of its proper divisors (26959370896596).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13121310501420 is a wasteful number, since it uses less digits than its factorization.
13121310501420 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 516911 (or 516909 counting only the distinct ones).
The product of its (nonzero) digits is 720, while the sum is 24.
Adding to 13121310501420 its reverse (2410501312131), we get a palindrome (15531811813551).
The spelling of 13121310501420 in words is "thirteen trillion, one hundred twenty-one billion, three hundred ten million, five hundred one thousand, four hundred twenty".
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