131213333114240 has 128 divisors (see below), whose sum is σ = 338534624020320. Its totient is φ = 48344255447040.

The previous prime is 131213333114233. The next prime is 131213333114249. The reversal of 131213333114240 is 42411333312131.

It is a tau number, because it is divible by the number of its divisors (128).

It is a super-2 number, since 2×131213333114240² (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (32).

It is a junction number, because it is equal to n+sod(n) for n = 131213333114197 and 131213333114206.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131213333114249) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 12999821 + ... + 20770700.

Almost surely, 2^{131213333114240} is an apocalyptic number.

131213333114240 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

131213333114240 is an abundant number, since it is smaller than the sum of its proper divisors (207321290906080).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131213333114240 is a wasteful number, since it uses less digits than its factorization.

131213333114240 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 33771020 (or 33771008 counting only the distinct ones).

The product of its (nonzero) digits is 15552, while the sum is 32.

Adding to 131213333114240 its reverse (42411333312131), we get a palindrome (173624666426371).

The spelling of 131213333114240 in words is "one hundred thirty-one trillion, two hundred thirteen billion, three hundred thirty-three million, one hundred fourteen thousand, two hundred forty".