Base | Representation |
---|---|
bin | 11000011100010001… |
… | …11101110011101110 |
3 | 1020212111121102202110 |
4 | 30032020331303232 |
5 | 203333231230410 |
6 | 10010032504450 |
7 | 643115202123 |
oct | 141610756356 |
9 | 36774542673 |
10 | 13122133230 |
11 | 5624113a08 |
12 | 26626ab126 |
13 | 131179489b |
14 | 8c6a7c74a |
15 | 51c029720 |
hex | 30e23dcee |
13122133230 has 128 divisors (see below), whose sum is σ = 34245348480. Its totient is φ = 3204956160.
The previous prime is 13122133201. The next prime is 13122133243. The reversal of 13122133230 is 3233122131.
It is a junction number, because it is equal to n+sod(n) for n = 13122133197 and 13122133206.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 15828456 + ... + 15829284.
It is an arithmetic number, because the mean of its divisors is an integer number (267541785).
Almost surely, 213122133230 is an apocalyptic number.
13122133230 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is a practical number, because each smaller number is the sum of distinct divisors of 13122133230, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (17122674240).
13122133230 is an abundant number, since it is smaller than the sum of its proper divisors (21123215250).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13122133230 is a wasteful number, since it uses less digits than its factorization.
13122133230 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1654.
The product of its (nonzero) digits is 648, while the sum is 21.
Adding to 13122133230 its reverse (3233122131), we get a palindrome (16355255361).
It can be divided in two parts, 131221 and 33230, that added together give a triangular number (164451 = T573).
The spelling of 13122133230 in words is "thirteen billion, one hundred twenty-two million, one hundred thirty-three thousand, two hundred thirty".
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