Base | Representation |
---|---|
bin | 11101110101101100011000… |
… | …010001101000000101011100 |
3 | 122012122202122200022100102020 |
4 | 131311230120101220011130 |
5 | 114200110424022044400 |
6 | 1143035400301500140 |
7 | 36433165242245262 |
oct | 3565543021500534 |
9 | 565582580270366 |
10 | 131233133003100 |
11 | 388a6728380a07 |
12 | 12875a3a871650 |
13 | 582c301346b6b |
14 | 2459a08c7a432 |
15 | 1028a1ce752a0 |
hex | 775b1846815c |
131233133003100 has 72 divisors (see below), whose sum is σ = 382249528474800. Its totient is φ = 34760632980480.
The previous prime is 131233133003003. The next prime is 131233133003101. The reversal of 131233133003100 is 1300331332131.
It is a super-2 number, since 2×1312331330031002 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131233133003101) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1467887437 + ... + 1467976836.
Almost surely, 2131233133003100 is an apocalyptic number.
131233133003100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
131233133003100 is an abundant number, since it is smaller than the sum of its proper divisors (251016395471700).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131233133003100 is a wasteful number, since it uses less digits than its factorization.
131233133003100 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2935864439 (or 2935864432 counting only the distinct ones).
The product of its (nonzero) digits is 1458, while the sum is 24.
Adding to 131233133003100 its reverse (1300331332131), we get a palindrome (132533464335231).
The spelling of 131233133003100 in words is "one hundred thirty-one trillion, two hundred thirty-three billion, one hundred thirty-three million, three thousand, one hundred".
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