Base | Representation |
---|---|
bin | 10011000110010011101… |
… | …101010001000011000100 |
3 | 11122110122102022120120212 |
4 | 103012103231101003010 |
5 | 133000340421023330 |
6 | 2442532243214552 |
7 | 163551364433321 |
oct | 23062355210304 |
9 | 4573572276525 |
10 | 1312443142340 |
11 | 466670a36200 |
12 | 19243a677458 |
13 | 969bbcc7465 |
14 | 47745d9bb48 |
15 | 2421652c295 |
hex | 13193b510c4 |
1312443142340 has 144 divisors (see below), whose sum is σ = 3227341440960. Its totient is φ = 446684832000.
The previous prime is 1312443142301. The next prime is 1312443142363. The reversal of 1312443142340 is 432413442131.
It is a junction number, because it is equal to n+sod(n) for n = 1312443142297 and 1312443142306.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 3644390 + ... + 3988290.
It is an arithmetic number, because the mean of its divisors is an integer number (22412093340).
Almost surely, 21312443142340 is an apocalyptic number.
1312443142340 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 1312443142340, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1613670720480).
1312443142340 is an abundant number, since it is smaller than the sum of its proper divisors (1914898298620).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1312443142340 is a wasteful number, since it uses less digits than its factorization.
1312443142340 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 344034 (or 344021 counting only the distinct ones).
The product of its (nonzero) digits is 27648, while the sum is 32.
Adding to 1312443142340 its reverse (432413442131), we get a palindrome (1744856584471).
The spelling of 1312443142340 in words is "one trillion, three hundred twelve billion, four hundred forty-three million, one hundred forty-two thousand, three hundred forty".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •