Base | Representation |
---|---|
bin | 111101000111101011… |
… | …1110011010000000000 |
3 | 110112210100022100221002 |
4 | 1322033113303100000 |
5 | 4122302111300000 |
6 | 140144125151132 |
7 | 12324414664133 |
oct | 1721727632000 |
9 | 415710270832 |
10 | 131254400000 |
11 | 50734761449 |
12 | 215309bb4a8 |
13 | c4b9a35059 |
14 | 64d1d1a21a |
15 | 36330478d5 |
hex | 1e8f5f3400 |
131254400000 has 132 divisors (see below), whose sum is σ = 327962782476. Its totient is φ = 52500480000.
The previous prime is 131254399999. The next prime is 131254400027. The reversal of 131254400000 is 4452131.
It can be written as a sum of positive squares in 6 ways, for example, as 93176341504 + 38078058496 = 305248^2 + 195136^2 .
It is a hoax number, since the sum of its digits (20) coincides with the sum of the digits of its distinct prime factors.
It is a Harshad number since it is a multiple of its sum of digits (20).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 3179492 + ... + 3220508.
Almost surely, 2131254400000 is an apocalyptic number.
131254400000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 131254400000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (163981391238).
131254400000 is an abundant number, since it is smaller than the sum of its proper divisors (196708382476).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131254400000 is an frugal number, since it uses more digits than its factorization.
131254400000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 41062 (or 41024 counting only the distinct ones).
The product of its (nonzero) digits is 480, while the sum is 20.
Adding to 131254400000 its reverse (4452131), we get a palindrome (131258852131).
The spelling of 131254400000 in words is "one hundred thirty-one billion, two hundred fifty-four million, four hundred thousand".
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