13130250340440 has 128 divisors (see below), whose sum is σ = 41164407567360. Its totient is φ = 3347206754304.

The previous prime is 13130250340381. The next prime is 13130250340511. The reversal of 13130250340440 is 4404305203131.

13130250340440 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a Harshad number since it is a multiple of its sum of digits (30).

It is a junction number, because it is equal to n+sod(n) for n = 13130250340398 and 13130250340407.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 26827929 + ... + 27312968.

It is an arithmetic number, because the mean of its divisors is an integer number (321596934120).

Almost surely, 2^{13130250340440} is an apocalyptic number.

13130250340440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13130250340440 is an abundant number, since it is smaller than the sum of its proper divisors (28034157226920).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13130250340440 is a wasteful number, since it uses less digits than its factorization.

13130250340440 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 54141001 (or 54140997 counting only the distinct ones).

The product of its (nonzero) digits is 17280, while the sum is 30.

Adding to 13130250340440 its reverse (4404305203131), we get a palindrome (17534555543571).

The spelling of 13130250340440 in words is "thirteen trillion, one hundred thirty billion, two hundred fifty million, three hundred forty thousand, four hundred forty".