Search a number
-
+
13131434543232 = 27360475655109
BaseRepresentation
bin1011111100010110011001…
…1111011100100010000000
31201111100112020210010021010
42333011212133130202000
53210121134220340412
643532255303000520
72523500121651465
oct277054637344200
951440466703233
1013131434543232
114203012511445
121580b62a39140
1374339ab145a5
143357c9c3566c
1517b8a341533c
hexbf1667dc880

13131434543232 has 64 divisors (see below), whose sum is σ = 34886147385600. Its totient is φ = 4376420219904.

The previous prime is 13131434543191. The next prime is 13131434543237. The reversal of 13131434543232 is 23234543413131.

It is a happy number.

13131434543232 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a tau number, because it is divible by the number of its divisors (64).

It is a super-3 number, since 3×131314345432323 (a number of 40 digits) contains 333 as substring.

It is not an unprimeable number, because it can be changed into a prime (13131434543237) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 505507 + ... + 5149602.

It is an arithmetic number, because the mean of its divisors is an integer number (545096052900).

Almost surely, 213131434543232 is an apocalyptic number.

13131434543232 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

13131434543232 is an abundant number, since it is smaller than the sum of its proper divisors (21754712842368).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13131434543232 is an equidigital number, since it uses as much as digits as its factorization.

13131434543232 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5661173 (or 5661161 counting only the distinct ones).

The product of its digits is 311040, while the sum is 39.

Adding to 13131434543232 its reverse (23234543413131), we get a palindrome (36365977956363).

The spelling of 13131434543232 in words is "thirteen trillion, one hundred thirty-one billion, four hundred thirty-four million, five hundred forty-three thousand, two hundred thirty-two".

Divisors: 1 2 3 4 6 8 12 16 24 32 48 64 96 128 192 384 6047 12094 18141 24188 36282 48376 72564 96752 145128 193504 290256 387008 580512 774016 1161024 2322048 5655109 11310218 16965327 22620436 33930654 45240872 67861308 90481744 135722616 180963488 271445232 361926976 542890464 723853952 1085780928 2171561856 34196444123 68392888246 102589332369 136785776492 205178664738 273571552984 410357329476 547143105968 820714658952 1094286211936 1641429317904 2188572423872 3282858635808 4377144847744 6565717271616 13131434543232