Base | Representation |
---|---|
bin | 1011111100011100010100… |
… | …0011010011100111110110 |
3 | 1201111111121210222120212210 |
4 | 2333013011003103213312 |
5 | 3210132411334032410 |
6 | 43533120534154250 |
7 | 2523554334433413 |
oct | 277070503234766 |
9 | 51444553876783 |
10 | 13133021002230 |
11 | 4203756a84588 |
12 | 15813261b2986 |
13 | 7435916b8b1c |
14 | 3358da80310a |
15 | 17b94783c220 |
hex | bf1c50d39f6 |
13133021002230 has 32 divisors (see below), whose sum is σ = 33373323959904. Its totient is φ = 3296130761216.
The previous prime is 13133021002207. The next prime is 13133021002301. The reversal of 13133021002230 is 3220012033131.
It is a junction number, because it is equal to n+sod(n) for n = 13133021002197 and 13133021002206.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 12875510277 + ... + 12875511296.
It is an arithmetic number, because the mean of its divisors is an integer number (1042916373747).
Almost surely, 213133021002230 is an apocalyptic number.
13133021002230 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13133021002230 is an abundant number, since it is smaller than the sum of its proper divisors (20240302957674).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13133021002230 is a wasteful number, since it uses less digits than its factorization.
13133021002230 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 25751021600.
The product of its (nonzero) digits is 648, while the sum is 21.
Adding to 13133021002230 its reverse (3220012033131), we get a palindrome (16353033035361).
The spelling of 13133021002230 in words is "thirteen trillion, one hundred thirty-three billion, twenty-one million, two thousand, two hundred thirty".
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