13143111433050 has 96 divisors (see below), whose sum is σ = 33672322404864. Its totient is φ = 3389154048000.

The previous prime is 13143111433043. The next prime is 13143111433091. The reversal of 13143111433050 is 5033411134131.

It is a Harshad number since it is a multiple of its sum of digits (30).

It is a junction number, because it is equal to n+sod(n) for n = 13143111432999 and 13143111433017.

It is an unprimeable number.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 4941430 + ... + 7120670.

It is an arithmetic number, because the mean of its divisors is an integer number (350753358384).

Almost surely, 2^{13143111433050} is an apocalyptic number.

13143111433050 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is a practical number, because each smaller number is the sum of distinct divisors of 13143111433050, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (16836161202432).

13143111433050 is an abundant number, since it is smaller than the sum of its proper divisors (20529210971814).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13143111433050 is a wasteful number, since it uses less digits than its factorization.

13143111433050 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2180584 (or 2180579 counting only the distinct ones).

The product of its (nonzero) digits is 6480, while the sum is 30.

Adding to 13143111433050 its reverse (5033411134131), we get a palindrome (18176522567181).

The spelling of 13143111433050 in words is "thirteen trillion, one hundred forty-three billion, one hundred eleven million, four hundred thirty-three thousand, fifty".