13200136406430 has 64 divisors (see below), whose sum is σ = 32155106139648. Its totient is φ = 3467289513600.

The previous prime is 13200136406417. The next prime is 13200136406437. The reversal of 13200136406430 is 3460463100231.

It is a super-2 number, since 2×13200136406430² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13200136406391 and 13200136406400.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13200136406437) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 34686264 + ... + 35064756.

It is an arithmetic number, because the mean of its divisors is an integer number (502423533432).

Almost surely, 2^{13200136406430} is an apocalyptic number.

13200136406430 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

13200136406430 is an abundant number, since it is smaller than the sum of its proper divisors (18954969733218).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13200136406430 is a wasteful number, since it uses less digits than its factorization.

13200136406430 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 395921.

The product of its (nonzero) digits is 31104, while the sum is 33.

Adding to 13200136406430 its reverse (3460463100231), we get a palindrome (16660599506661).

The spelling of 13200136406430 in words is "thirteen trillion, two hundred billion, one hundred thirty-six million, four hundred six thousand, four hundred thirty".