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13201233360150 = 23521122812588401
BaseRepresentation
bin1100000000011010011011…
…0100110011010100010110
31201202000200122120101211110
43000012212310303110112
53212242111220011100
644024321325515450
72531520604055523
oct300064664632426
951660618511743
1013201233360150
11422a680092700
1215925a2412b86
13749b4267c2a4
14338d2bc3c14a
1517d5db036250
hexc01a6d33516

13201233360150 has 144 divisors (see below), whose sum is σ = 36113985213264. Its totient is φ = 3188908800000.

The previous prime is 13201233360149. The next prime is 13201233360191. The reversal of 13201233360150 is 5106333210231.

It is a super-3 number, since 3×132012333601503 (a number of 40 digits) contains 333 as substring.

It is a Harshad number since it is a multiple of its sum of digits (30).

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 3805950 + ... + 6394350.

It is an arithmetic number, because the mean of its divisors is an integer number (250791563981).

Almost surely, 213201233360150 is an apocalyptic number.

13201233360150 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is a practical number, because each smaller number is the sum of distinct divisors of 13201233360150, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (18056992606632).

13201233360150 is an abundant number, since it is smaller than the sum of its proper divisors (22912751853114).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13201233360150 is a wasteful number, since it uses less digits than its factorization.

13201233360150 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2588719 (or 2588703 counting only the distinct ones).

The product of its (nonzero) digits is 9720, while the sum is 30.

Adding to 13201233360150 its reverse (5106333210231), we get a palindrome (18307566570381).

The spelling of 13201233360150 in words is "thirteen trillion, two hundred one billion, two hundred thirty-three million, three hundred sixty thousand, one hundred fifty".

Divisors: 1 2 3 5 6 10 11 15 22 25 30 33 50 55 66 75 110 121 150 165 242 275 281 330 363 550 562 605 726 825 843 1210 1405 1650 1686 1815 2810 3025 3091 3630 4215 6050 6182 7025 8430 9075 9273 14050 15455 18150 18546 21075 30910 34001 42150 46365 68002 77275 92730 102003 154550 170005 204006 231825 340010 463650 510015 850025 1020030 1700050 2550075 2588401 5100150 5176802 7765203 12942005 15530406 25884010 28472411 38826015 56944822 64710025 77652030 85417233 129420050 142362055 170834466 194130075 284724110 313196521 388260150 427086165 626393042 711810275 727340681 854172330 939589563 1423620550 1454681362 1565982605 1879179126 2135430825 2182022043 3131965210 3636703405 4270861650 4364044086 4697947815 7273406810 7829913025 8000747491 9395895630 10910110215 15659826050 16001494982 18183517025 21820220430 23489739075 24002242473 36367034050 40003737455 46979478150 48004484946 54550551075 80007474910 88008222401 109101102150 120011212365 176016444802 200018687275 240022424730 264024667203 400037374550 440041112005 528049334406 600056061825 880082224010 1200112123650 1320123336015 2200205560025 2640246672030 4400411120050 6600616680075 13201233360150