Base | Representation |
---|---|
bin | 11000100110111010… |
… | …01110101100000010 |
3 | 1021002201110011112210 |
4 | 30103131032230002 |
5 | 204024100100310 |
6 | 10022540402550 |
7 | 645250314651 |
oct | 142335165402 |
9 | 37081404483 |
10 | 13211331330 |
11 | 566a4a784a |
12 | 2688546456 |
13 | 13270c5822 |
14 | 8d485b198 |
15 | 524c98820 |
hex | 31374eb02 |
13211331330 has 64 divisors (see below), whose sum is σ = 33646648320. Its totient is φ = 3312720576.
The previous prime is 13211331323. The next prime is 13211331373. The reversal of 13211331330 is 3313311231.
It is a super-2 number, since 2×132113313302 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13211331297 and 13211331306.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 121552 + ... + 202971.
It is an arithmetic number, because the mean of its divisors is an integer number (525728880).
Almost surely, 213211331330 is an apocalyptic number.
13211331330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13211331330 is an abundant number, since it is smaller than the sum of its proper divisors (20435316990).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13211331330 is a wasteful number, since it uses less digits than its factorization.
13211331330 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 324615.
The product of its (nonzero) digits is 486, while the sum is 21.
Adding to 13211331330 its reverse (3313311231), we get a palindrome (16524642561).
The spelling of 13211331330 in words is "thirteen billion, two hundred eleven million, three hundred thirty-one thousand, three hundred thirty".
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