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132140403131120 = 2454759595656343
BaseRepresentation
bin11110000010111001010101…
…110010100000001011110000
3122022212111110220010012102022
4132002321111302200023300
5114304442021200143440
61145012244013211012
736555554242141316
oct3602712562401360
9568774426105368
10132140403131120
113911648074656a
12129a1841790a68
135896a2c078067
14248b8b5a180b6
15104241d878cb5
hex782e55ca02f0

132140403131120 has 80 divisors (see below), whose sum is σ = 319081190353920. Its totient is φ = 50854755854592.

The previous prime is 132140403131081. The next prime is 132140403131123. The reversal of 132140403131120 is 21131304041231.

It is a tau number, because it is divible by the number of its divisors (80).

It is a super-2 number, since 2×1321404031311202 (a number of 29 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 132140403131120.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (132140403131123) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 297606332 + ... + 298050011.

It is an arithmetic number, because the mean of its divisors is an integer number (3988514879424).

Almost surely, 2132140403131120 is an apocalyptic number.

132140403131120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

132140403131120 is an abundant number, since it is smaller than the sum of its proper divisors (186940787222800).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

132140403131120 is a wasteful number, since it uses less digits than its factorization.

132140403131120 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 595656462 (or 595656456 counting only the distinct ones).

The product of its (nonzero) digits is 1728, while the sum is 26.

Adding to 132140403131120 its reverse (21131304041231), we get a palindrome (153271707172351).

The spelling of 132140403131120 in words is "one hundred thirty-two trillion, one hundred forty billion, four hundred three million, one hundred thirty-one thousand, one hundred twenty".

Divisors: 1 2 4 5 8 10 16 20 40 47 59 80 94 118 188 235 236 295 376 470 472 590 752 940 944 1180 1880 2360 2773 3760 4720 5546 11092 13865 22184 27730 44368 55460 110920 221840 595656343 1191312686 2382625372 2978281715 4765250744 5956563430 9530501488 11913126860 23826253720 27995848121 35143724237 47652507440 55991696242 70287448474 111983392484 139979240605 140574896948 175718621185 223966784968 279958481210 281149793896 351437242370 447933569936 559916962420 562299587792 702874484740 1119833924840 1405748969480 1651755039139 2239667849680 2811497938960 3303510078278 6607020156556 8258775195695 13214040313112 16517550391390 26428080626224 33035100782780 66070201565560 132140403131120