Base | Representation |
---|---|
bin | 1100000010011001101101… |
… | …1000110011101010110110 |
3 | 1201212021212212102001010012 |
4 | 3000212123120303222312 |
5 | 3213322100202214200 |
6 | 44052132005300222 |
7 | 2534140403024651 |
oct | 300463330635266 |
9 | 51767785361105 |
10 | 13235401210550 |
11 | 4243113a343a2 |
12 | 1599139104672 |
13 | 75012937484c |
14 | 33a84da10898 |
15 | 17e43a9dda35 |
hex | c099b633ab6 |
13235401210550 has 96 divisors (see below), whose sum is σ = 25049370880512. Its totient is φ = 5201783009280.
The previous prime is 13235401210523. The next prime is 13235401210561. The reversal of 13235401210550 is 5501210453231.
13235401210550 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a Curzon number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 2650788854 + ... + 2650793846.
It is an arithmetic number, because the mean of its divisors is an integer number (260930946672).
Almost surely, 213235401210550 is an apocalyptic number.
13235401210550 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13235401210550 is a deficient number, since it is larger than the sum of its proper divisors (11813969669962).
13235401210550 is a wasteful number, since it uses less digits than its factorization.
13235401210550 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6942 (or 6937 counting only the distinct ones).
The product of its (nonzero) digits is 18000, while the sum is 32.
Adding to 13235401210550 its reverse (5501210453231), we get a palindrome (18736611663781).
The spelling of 13235401210550 in words is "thirteen trillion, two hundred thirty-five billion, four hundred one million, two hundred ten thousand, five hundred fifty".
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