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132355312000 = 275325132957
BaseRepresentation
bin111101101000011111…
…1011100100110000000
3110122122001212111021121
41323100333130212000
54132030424441000
6140445253402024
712363613406122
oct1732077344600
9418561774247
10132355312000
115114a13997a
1221799639314
13c633b44b82
146598215212
153699a0db1a
hex1ed0fdc980

132355312000 has 128 divisors (see below), whose sum is σ = 330389448480. Its totient is φ = 52729600000.

The previous prime is 132355311989. The next prime is 132355312039. The reversal of 132355312000 is 213553231.

It is a tau number, because it is divible by the number of its divisors (128).

It is a super-2 number, since 2×1323553120002 (a number of 23 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (25).

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3999522 + ... + 4032478.

Almost surely, 2132355312000 is an apocalyptic number.

132355312000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 132355312000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (165194724240).

132355312000 is an abundant number, since it is smaller than the sum of its proper divisors (198034136480).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

132355312000 is an equidigital number, since it uses as much as digits as its factorization.

132355312000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 33237 (or 33215 counting only the distinct ones).

The product of its (nonzero) digits is 2700, while the sum is 25.

Adding to 132355312000 its reverse (213553231), we get a palindrome (132568865231).

It can be divided in two parts, 13235 and 5312000, that added together give a palindrome (5325235).

The spelling of 132355312000 in words is "one hundred thirty-two billion, three hundred fifty-five million, three hundred twelve thousand".

Divisors: 1 2 4 5 8 10 16 20 25 32 40 50 64 80 100 125 128 160 200 250 251 320 400 500 502 640 800 1000 1004 1255 1600 2000 2008 2510 3200 4000 4016 5020 6275 8000 8032 10040 12550 16000 16064 20080 25100 31375 32128 32957 40160 50200 62750 65914 80320 100400 125500 131828 160640 164785 200800 251000 263656 329570 401600 502000 527312 659140 803200 823925 1004000 1054624 1318280 1647850 2008000 2109248 2636560 3295700 4016000 4119625 4218496 5273120 6591400 8239250 8272207 10546240 13182800 16478500 16544414 21092480 26365600 32957000 33088828 41361035 52731200 65914000 66177656 82722070 105462400 131828000 132355312 165444140 206805175 263656000 264710624 330888280 413610350 527312000 529421248 661776560 827220700 1034025875 1058842496 1323553120 1654441400 2068051750 2647106240 3308882800 4136103500 5294212480 6617765600 8272207000 13235531200 16544414000 26471062400 33088828000 66177656000 132355312000