Base | Representation |
---|---|
bin | 1100000110001011110110… |
… | …1100110110101001100110 |
3 | 1202002111122211201210212220 |
4 | 3001202331230312221212 |
5 | 3220403210224303142 |
6 | 44142041533053210 |
7 | 2541631226360463 |
oct | 301427554665146 |
9 | 52074584653786 |
10 | 13300401400422 |
11 | 4268739939084 |
12 | 15a9859627206 |
13 | 7562b79c8b66 |
14 | 33da585b466a |
15 | 180e921d42ec |
hex | c18bdb36a66 |
13300401400422 has 32 divisors (see below), whose sum is σ = 29647953590400. Its totient is φ = 3953060477568.
The previous prime is 13300401400333. The next prime is 13300401400469. The reversal of 13300401400422 is 22400410400331.
It is a junction number, because it is equal to n+sod(n) for n = 13300401400392 and 13300401400401.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3431474172 + ... + 3431478047.
It is an arithmetic number, because the mean of its divisors is an integer number (926498549700).
Almost surely, 213300401400422 is an apocalyptic number.
13300401400422 is an abundant number, since it is smaller than the sum of its proper divisors (16347552189978).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13300401400422 is a wasteful number, since it uses less digits than its factorization.
13300401400422 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6862952260.
The product of its (nonzero) digits is 2304, while the sum is 24.
Adding to 13300401400422 its reverse (22400410400331), we get a palindrome (35700811800753).
The spelling of 13300401400422 in words is "thirteen trillion, three hundred billion, four hundred one million, four hundred thousand, four hundred twenty-two".
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