Base | Representation |
---|---|
bin | 11110001111101110100101… |
… | …110100000001001001011000 |
3 | 122102222210120210211202012121 |
4 | 132033232211310001021120 |
5 | 114413413443241014430 |
6 | 1150525321140351024 |
7 | 40006352316644554 |
oct | 3617564564011130 |
9 | 572883523752177 |
10 | 133022214001240 |
11 | 39426449a15913 |
12 | 12b0471a3a5474 |
13 | 592bc30384205 |
14 | 24bc449420864 |
15 | 105a32e0dda7a |
hex | 78fba5d01258 |
133022214001240 has 64 divisors (see below), whose sum is σ = 333585118735200. Its totient is φ = 47443216877568.
The previous prime is 133022214001219. The next prime is 133022214001289. The reversal of 133022214001240 is 42100412220331.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5147905579 + ... + 5147931418.
Almost surely, 2133022214001240 is an apocalyptic number.
133022214001240 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
133022214001240 is an abundant number, since it is smaller than the sum of its proper divisors (200562904733960).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
133022214001240 is a wasteful number, since it uses less digits than its factorization.
133022214001240 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10295837044 (or 10295837040 counting only the distinct ones).
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 133022214001240 its reverse (42100412220331), we get a palindrome (175122626221571).
The spelling of 133022214001240 in words is "one hundred thirty-three trillion, twenty-two billion, two hundred fourteen million, one thousand, two hundred forty".
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