133055641540350 has 72 divisors (see below), whose sum is σ = 378504166191840. Its totient is φ = 33394357090560.

The previous prime is 133055641540313. The next prime is 133055641540351. The reversal of 133055641540350 is 53045146550331.

133055641540350 is a `hidden beast` number, since 1 + 3 + 3 + 0 + 5 + 56 + 4 + 1 + 540 + 3 + 50 = 666.

It is a super-3 number, since 3×133055641540350³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Harshad number since it is a multiple of its sum of digits (45).

It is a junction number, because it is equal to n+sod(n) for n = 133055641540296 and 133055641540305.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (133055641540351) by changing a digit.

It is a polite number, since it can be written in 35 ways as a sum of consecutive naturals, for example, 8696439510 + ... + 8696454809.

It is an arithmetic number, because the mean of its divisors is an integer number (5257002308220).

Almost surely, 2^{133055641540350} is an apocalyptic number.

133055641540350 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

133055641540350 is an abundant number, since it is smaller than the sum of its proper divisors (245448524651490).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

133055641540350 is a wasteful number, since it uses less digits than its factorization.

133055641540350 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17392894354 (or 17392894346 counting only the distinct ones).

The product of its (nonzero) digits is 1620000, while the sum is 45.

The spelling of 133055641540350 in words is "one hundred thirty-three trillion, fifty-five billion, six hundred forty-one million, five hundred forty thousand, three hundred fifty".