Base | Representation |
---|---|
bin | 10011100000000100111… |
… | …011010001101011100100 |
3 | 11202010001201222202002010 |
4 | 103200010323101223210 |
5 | 133424022241203012 |
6 | 2503350020314220 |
7 | 165551143553550 |
oct | 23400473215344 |
9 | 4663051882063 |
10 | 1340112444132 |
11 | 47737a5a1170 |
12 | 197880b42970 |
13 | 994ab559697 |
14 | 48c0ca66860 |
15 | 24cd571dc3c |
hex | 13804ed1ae4 |
1340112444132 has 96 divisors (see below), whose sum is σ = 3907310367744. Its totient is φ = 347295312000.
The previous prime is 1340112444127. The next prime is 1340112444191. The reversal of 1340112444132 is 2314442110431.
It is a happy number.
It is a self number, because there is not a number n which added to its sum of digits gives 1340112444132.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1227619 + ... + 2046282.
It is an arithmetic number, because the mean of its divisors is an integer number (40701149664).
Almost surely, 21340112444132 is an apocalyptic number.
1340112444132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
1340112444132 is an abundant number, since it is smaller than the sum of its proper divisors (2567197923612).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1340112444132 is a wasteful number, since it uses less digits than its factorization.
1340112444132 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3274369 (or 3274367 counting only the distinct ones).
The product of its (nonzero) digits is 9216, while the sum is 30.
Adding to 1340112444132 its reverse (2314442110431), we get a palindrome (3654554554563).
The spelling of 1340112444132 in words is "one trillion, three hundred forty billion, one hundred twelve million, four hundred forty-four thousand, one hundred thirty-two".
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