1340312012000 has 96 divisors (see below), whose sum is σ = 3546465721344. Its totient is φ = 494884416000.

The previous prime is 1340312011979. The next prime is 1340312012027. The reversal of 1340312012000 is 2102130431.

It is a super-2 number, since 2×1340312012000² (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1340312012000.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 12835616 + ... + 12939615.

It is an arithmetic number, because the mean of its divisors is an integer number (36942351264).

Almost surely, 2^{1340312012000} is an apocalyptic number.

1340312012000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

1340312012000 is an abundant number, since it is smaller than the sum of its proper divisors (2206153709344).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1340312012000 is a wasteful number, since it uses less digits than its factorization.

1340312012000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 25775269 (or 25775251 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 1340312012000 its reverse (2102130431), we get a palindrome (1342414142431).

The spelling of 1340312012000 in words is "one trillion, three hundred forty billion, three hundred twelve million, twelve thousand".