Base | Representation |
---|---|
bin | 1100001100100111111100… |
… | …1010110010000011011000 |
3 | 1202111002012010211121022110 |
4 | 3003021333022302003120 |
5 | 3224211232441243000 |
6 | 44304534352152320 |
7 | 2552625420204324 |
oct | 303117712620330 |
9 | 52432163747273 |
10 | 13411021431000 |
11 | 4300644a78356 |
12 | 160718bb386a0 |
13 | 7638667b595b |
14 | 34514dc76984 |
15 | 183cb8954850 |
hex | c327f2b20d8 |
13411021431000 has 64 divisors (see below), whose sum is σ = 41842386874080. Its totient is φ = 3576272380800.
The previous prime is 13411021430993. The next prime is 13411021431083. The reversal of 13411021431000 is 13412011431.
It is a super-2 number, since 2×134110214310002 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2235167239 + ... + 2235173238.
Almost surely, 213411021431000 is an apocalyptic number.
13411021431000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13411021431000 is an abundant number, since it is smaller than the sum of its proper divisors (28431365443080).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13411021431000 is a wasteful number, since it uses less digits than its factorization.
13411021431000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4470340501 (or 4470340487 counting only the distinct ones).
The product of its (nonzero) digits is 288, while the sum is 21.
Adding to 13411021431000 its reverse (13412011431), we get a palindrome (13424433442431).
The spelling of 13411021431000 in words is "thirteen trillion, four hundred eleven billion, twenty-one million, four hundred thirty-one thousand".
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