Base | Representation |
---|---|
bin | 1100001101110100010001… |
… | …1010001101001110100010 |
3 | 1202120001002001112212122200 |
4 | 3003131010122031032202 |
5 | 3230030213134031302 |
6 | 44322203431114030 |
7 | 2554252231062630 |
oct | 303350432151642 |
9 | 52501061485580 |
10 | 13431510455202 |
11 | 43092a9547504 |
12 | 160b149812916 |
13 | 7657805a1908 |
14 | 346135098350 |
15 | 1845b75bb81c |
hex | c374468d3a2 |
13431510455202 has 96 divisors (see below), whose sum is σ = 36429712675200. Its totient is φ = 3487288702464.
The previous prime is 13431510455201. The next prime is 13431510455239. The reversal of 13431510455202 is 20255401513431.
13431510455202 is a `hidden beast` number, since 1 + 3 + 43 + 1 + 51 + 0 + 45 + 520 + 2 = 666.
It is a super-3 number, since 3×134315104552023 (a number of 40 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (13431510455201) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 108050752 + ... + 108174987.
It is an arithmetic number, because the mean of its divisors is an integer number (379476173700).
Almost surely, 213431510455202 is an apocalyptic number.
13431510455202 is an abundant number, since it is smaller than the sum of its proper divisors (22998202219998).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13431510455202 is a wasteful number, since it uses less digits than its factorization.
13431510455202 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 216225800 (or 216225797 counting only the distinct ones).
The product of its (nonzero) digits is 72000, while the sum is 36.
Adding to 13431510455202 its reverse (20255401513431), we get a palindrome (33686911968633).
The spelling of 13431510455202 in words is "thirteen trillion, four hundred thirty-one billion, five hundred ten million, four hundred fifty-five thousand, two hundred two".
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