Base | Representation |
---|---|
bin | 10011100011001001101… |
… | …110001111110010000000 |
3 | 11202102120211201021101110 |
4 | 103203021232033302000 |
5 | 134002303004440112 |
6 | 2505053403203320 |
7 | 166026024531246 |
oct | 23431156176200 |
9 | 4672524637343 |
10 | 1343414140032 |
11 | 478814294168 |
12 | 198442816540 |
13 | 998b65b38b3 |
14 | 49043364796 |
15 | 24e2a50913c |
hex | 138c9b8fc80 |
1343414140032 has 32 divisors (see below), whose sum is σ = 3568443810480. Its totient is φ = 447804713216.
The previous prime is 1343414139967. The next prime is 1343414140063. The reversal of 1343414140032 is 2300414143431.
It is a tau number, because it is divible by the number of its divisors (32).
It is a super-2 number, since 2×13434141400322 (a number of 25 digits) contains 22 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1749236778 + ... + 1749237545.
Almost surely, 21343414140032 is an apocalyptic number.
1343414140032 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
1343414140032 is an abundant number, since it is smaller than the sum of its proper divisors (2225029670448).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1343414140032 is an equidigital number, since it uses as much as digits as its factorization.
1343414140032 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3498474340 (or 3498474328 counting only the distinct ones).
The product of its (nonzero) digits is 13824, while the sum is 30.
Adding to 1343414140032 its reverse (2300414143431), we get a palindrome (3643828283463).
The spelling of 1343414140032 in words is "one trillion, three hundred forty-three billion, four hundred fourteen million, one hundred forty thousand, thirty-two".
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