Base | Representation |
---|---|
bin | 10011100011110010000… |
… | …110001010011110111100 |
3 | 11202111100001021122102110 |
4 | 103203302012022132330 |
5 | 134010144410422203 |
6 | 2505244521254020 |
7 | 166051561142130 |
oct | 23436206123674 |
9 | 4674301248373 |
10 | 1344091498428 |
11 | 479031679598 |
12 | 1985b1634310 |
13 | 99993a26393 |
14 | 490a92c73c0 |
15 | 24e69c07d03 |
hex | 138f218a7bc |
1344091498428 has 144 divisors (see below), whose sum is σ = 3784666389504. Its totient is φ = 363636397440.
The previous prime is 1344091498417. The next prime is 1344091498471. The reversal of 1344091498428 is 8248941904431.
It is a super-2 number, since 2×13440914984282 (a number of 25 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (57).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 69341298 + ... + 69360678.
Almost surely, 21344091498428 is an apocalyptic number.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 1344091498428, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1892333194752).
1344091498428 is an abundant number, since it is smaller than the sum of its proper divisors (2440574891076).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1344091498428 is a wasteful number, since it uses less digits than its factorization.
1344091498428 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 21720 (or 21699 counting only the distinct ones).
The product of its (nonzero) digits is 7962624, while the sum is 57.
The spelling of 1344091498428 in words is "one trillion, three hundred forty-four billion, ninety-one million, four hundred ninety-eight thousand, four hundred twenty-eight".
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