Base | Representation |
---|---|
bin | 11110100100000100101010… |
… | …010111101000011110110110 |
3 | 122121221110021222122010002221 |
4 | 132210010222113220132312 |
5 | 120104320234342113420 |
6 | 1153515500120552554 |
7 | 40212355254265060 |
oct | 3644045227503666 |
9 | 577843258563087 |
10 | 134420302301110 |
11 | 3991536a356541 |
12 | 130ab67b32275a |
13 | 5a00a1abbbb77 |
14 | 2529d97b98730 |
15 | 10818a94cdcaa |
hex | 7a412a5e87b6 |
134420302301110 has 64 divisors (see below), whose sum is σ = 291079152852480. Its totient is φ = 43660789620480.
The previous prime is 134420302301069. The next prime is 134420302301123. The reversal of 134420302301110 is 11103203024431.
It is a super-3 number, since 3×1344203023011103 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 114577090 + ... + 115744330.
It is an arithmetic number, because the mean of its divisors is an integer number (4548111763320).
Almost surely, 2134420302301110 is an apocalyptic number.
134420302301110 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
134420302301110 is an abundant number, since it is smaller than the sum of its proper divisors (156658850551370).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
134420302301110 is a wasteful number, since it uses less digits than its factorization.
134420302301110 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1253861.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 134420302301110 its reverse (11103203024431), we get a palindrome (145523505325541).
The spelling of 134420302301110 in words is "one hundred thirty-four trillion, four hundred twenty billion, three hundred two million, three hundred one thousand, one hundred ten".
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