Base | Representation |
---|---|
bin | 111110110100101011… |
… | …0000101111100000110 |
3 | 110220020012120110201221 |
4 | 1331221112011330012 |
5 | 4202244303312400 |
6 | 141551043110554 |
7 | 12514141566040 |
oct | 1755126057406 |
9 | 426205513657 |
10 | 134911385350 |
11 | 52240a61695 |
12 | 2219167245a |
13 | c950577c01 |
14 | 675b8a0a90 |
15 | 3799113c1a |
hex | 1f69585f06 |
134911385350 has 48 divisors (see below), whose sum is σ = 291643833600. Its totient is φ = 45471336480.
The previous prime is 134911385327. The next prime is 134911385381. The reversal of 134911385350 is 53583119431.
134911385350 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 134911385297 and 134911385306.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 3245970 + ... + 3287269.
It is an arithmetic number, because the mean of its divisors is an integer number (6075913200).
Almost surely, 2134911385350 is an apocalyptic number.
134911385350 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
134911385350 is an abundant number, since it is smaller than the sum of its proper divisors (156732448250).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
134911385350 is a wasteful number, since it uses less digits than its factorization.
134911385350 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6533317 (or 6533312 counting only the distinct ones).
The product of its (nonzero) digits is 194400, while the sum is 43.
The spelling of 134911385350 in words is "one hundred thirty-four billion, nine hundred eleven million, three hundred eighty-five thousand, three hundred fifty".
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