Base | Representation |
---|---|
bin | 11001001000101101… |
… | …01000100001010000 |
3 | 1021211110212121202120 |
4 | 30210112220201100 |
5 | 210114133033200 |
6 | 10111024414240 |
7 | 655262014245 |
oct | 144426504120 |
9 | 37743777676 |
10 | 13494814800 |
11 | 57a5520105 |
12 | 2747477380 |
13 | 1370a5c91c |
14 | 9203715cc |
15 | 53eae39a0 |
hex | 3245a8850 |
13494814800 has 60 divisors (see below), whose sum is σ = 43228393920. Its totient is φ = 3598616960.
The previous prime is 13494814787. The next prime is 13494814807. The reversal of 13494814800 is 841849431.
It is a tau number, because it is divible by the number of its divisors (60).
It is a super-2 number, since 2×134948148002 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13494814807) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 5621640 + ... + 5624039.
It is an arithmetic number, because the mean of its divisors is an integer number (720473232).
Almost surely, 213494814800 is an apocalyptic number.
13494814800 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13494814800 is an abundant number, since it is smaller than the sum of its proper divisors (29733579120).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13494814800 is a wasteful number, since it uses less digits than its factorization.
13494814800 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11245700 (or 11245689 counting only the distinct ones).
The product of its (nonzero) digits is 110592, while the sum is 42.
The spelling of 13494814800 in words is "thirteen billion, four hundred ninety-four million, eight hundred fourteen thousand, eight hundred".
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